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0.2x^2=180
We move all terms to the left:
0.2x^2-(180)=0
a = 0.2; b = 0; c = -180;
Δ = b2-4ac
Δ = 02-4·0.2·(-180)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12}{2*0.2}=\frac{-12}{0.4} =-30 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12}{2*0.2}=\frac{12}{0.4} =30 $
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